4x-3(4-3x)=5(x-3)-29

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Solution for 4x-3(4-3x)=5(x-3)-29 equation: 



4x-3(4-3x)=5(x-3)-29

We move all terms to the left:

4x-3(4-3x)-(5(x-3)-29)=0

We add all the numbers together, and all the variables

4x-3(-3x+4)-(5(x-3)-29)=0

We multiply parentheses

4x+9x-(5(x-3)-29)-12=0



We calculate terms in parentheses: -(5(x-3)-29), so:

5(x-3)-29

We multiply parentheses

5x-15-29

We add all the numbers together, and all the variables

5x-44

Back to the equation:

-(5x-44)



We add all the numbers together, and all the variables

13x-(5x-44)-12=0

We get rid of parentheses

13x-5x+44-12=0

We add all the numbers together, and all the variables

8x+32=0

We move all terms containing x to the left, all other terms to the right

8x=-32

x=-32/8

x=-4

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