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4x-3(5-x)=2(x-6)
We move all terms to the left:
4x-3(5-x)-(2(x-6))=0
We add all the numbers together, and all the variables
4x-3(-1x+5)-(2(x-6))=0
We multiply parentheses
4x+3x-(2(x-6))-15=0
We calculate terms in parentheses: -(2(x-6)), so:We add all the numbers together, and all the variables
2(x-6)
We multiply parentheses
2x-12
Back to the equation:
-(2x-12)
7x-(2x-12)-15=0
We get rid of parentheses
7x-2x+12-15=0
We add all the numbers together, and all the variables
5x-3=0
We move all terms containing x to the left, all other terms to the right
5x=3
x=3/5
x=3/5
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