4x-3(x+1)=2(x-3)-x

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Solution for 4x-3(x+1)=2(x-3)-x equation:


Simplifying
4x + -3(x + 1) = 2(x + -3) + -1x

Reorder the terms:
4x + -3(1 + x) = 2(x + -3) + -1x
4x + (1 * -3 + x * -3) = 2(x + -3) + -1x
4x + (-3 + -3x) = 2(x + -3) + -1x

Reorder the terms:
-3 + 4x + -3x = 2(x + -3) + -1x

Combine like terms: 4x + -3x = 1x
-3 + 1x = 2(x + -3) + -1x

Reorder the terms:
-3 + 1x = 2(-3 + x) + -1x
-3 + 1x = (-3 * 2 + x * 2) + -1x
-3 + 1x = (-6 + 2x) + -1x

Combine like terms: 2x + -1x = 1x
-3 + 1x = -6 + 1x

Add '-1x' to each side of the equation.
-3 + 1x + -1x = -6 + 1x + -1x

Combine like terms: 1x + -1x = 0
-3 + 0 = -6 + 1x + -1x
-3 = -6 + 1x + -1x

Combine like terms: 1x + -1x = 0
-3 = -6 + 0
-3 = -6

Solving
-3 = -6

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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