4x-3(x+3)=-40-x=7

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Solution for 4x-3(x+3)=-40-x=7 equation: 



4x-3(x+3)=-40-x=7

We move all terms to the left:

4x-3(x+3)-(-40-x)=0

We add all the numbers together, and all the variables

4x-3(x+3)-(-1x-40)=0

We multiply parentheses

4x-3x-(-1x-40)-9=0

We get rid of parentheses

4x-3x+1x+40-9=0

We add all the numbers together, and all the variables

2x+31=0

We move all terms containing x to the left, all other terms to the right

2x=-31

x=-31/2

x=-15+1/2

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