4x-3(x+4)=3(x-6)-2

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Solution for 4x-3(x+4)=3(x-6)-2 equation: 



4x-3(x+4)=3(x-6)-2

We move all terms to the left:

4x-3(x+4)-(3(x-6)-2)=0

We multiply parentheses

4x-3x-(3(x-6)-2)-12=0



We calculate terms in parentheses: -(3(x-6)-2), so:

3(x-6)-2

We multiply parentheses

3x-18-2

We add all the numbers together, and all the variables

3x-20

Back to the equation:

-(3x-20)



We add all the numbers together, and all the variables

x-(3x-20)-12=0

We get rid of parentheses

x-3x+20-12=0

We add all the numbers together, and all the variables

-2x+8=0

We move all terms containing x to the left, all other terms to the right

-2x=-8

x=-8/-2

x=+4

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