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4x-3(x+4)=9(x-2)
We move all terms to the left:
4x-3(x+4)-(9(x-2))=0
We multiply parentheses
4x-3x-(9(x-2))-12=0
We calculate terms in parentheses: -(9(x-2)), so:We add all the numbers together, and all the variables
9(x-2)
We multiply parentheses
9x-18
Back to the equation:
-(9x-18)
x-(9x-18)-12=0
We get rid of parentheses
x-9x+18-12=0
We add all the numbers together, and all the variables
-8x+6=0
We move all terms containing x to the left, all other terms to the right
-8x=-6
x=-6/-8
x=3/4
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