4x-3(x-4)=3x+4x+12

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Solution for 4x-3(x-4)=3x+4x+12 equation: 



4x-3(x-4)=3x+4x+12

We move all terms to the left:

4x-3(x-4)-(3x+4x+12)=0

We add all the numbers together, and all the variables

4x-3(x-4)-(7x+12)=0

We multiply parentheses

4x-3x-(7x+12)+12=0

We get rid of parentheses

4x-3x-7x-12+12=0

We add all the numbers together, and all the variables

-6x=0

x=0/-6

x=0

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