4x-3/1-6x=x-7/x+9

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Solution for 4x-3/1-6x=x-7/x+9 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

4*x-(6*x)-(3/1) = x-(7/x)+9 // - x-(7/x)+9

4*x-(6*x)-x+7/x-(3/1)-9 = 0

4*x-6*x-x+7/x-9-3 = 0

7*x^-1-3*x^1-12*x^0 = 0

(7*x^0-3*x^2-12*x^1)/(x^1) = 0 // * x^2

x^1*(7*x^0-3*x^2-12*x^1) = 0

x^1

7-3*x^2-12*x = 0

7-3*x^2-12*x = 0

DELTA = (-12)^2-(-3*4*7)

DELTA = 228

DELTA > 0

x = (228^(1/2)+12)/(-3*2) or x = (12-228^(1/2))/(-3*2)

x = (2*57^(1/2)+12)/(-6) or x = (12-2*57^(1/2))/(-6)

x in { (2*57^(1/2)+12)/(-6), (12-2*57^(1/2))/(-6)} 

x in { (2*57^(1/2)+12)/(-6), (12-2*57^(1/2))/(-6) }

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