4x-3/2x+1+1-10(2x+1)/4x-3=3

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Solution for 4x-3/2x+1+1-10(2x+1)/4x-3=3 equation: 



4x-3/2x+1+1-10(2x+1)/4x-3=3

We move all terms to the left:

4x-3/2x+1+1-10(2x+1)/4x-3-(3)=0



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R





Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R



We add all the numbers together, and all the variables

4x-3/2x-10(2x+1)/4x-4=0

We calculate fractions


(-40x^2-20x)/8x^2+4x+(-12x)/8x^2-4=0

We multiply all the terms by the denominator


(-40x^2-20x)+4x*8x^2+(-12x)-4*8x^2=0

Wy multiply elements

(-40x^2-20x)+32x^3-32x^2+(-12x)=0

We get rid of parentheses

-40x^2+32x^3-32x^2-20x-12x=0

We do not support expression: x^3

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