4x-3/7x+4=9x+1/8x

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Solution for 4x-3/7x+4=9x+1/8x equation:



4x-3/7x+4=9x+1/8x
We move all terms to the left:
4x-3/7x+4-(9x+1/8x)=0
Domain of the equation: 7x!=0
x!=0/7
x!=0
x∈R
Domain of the equation: 8x)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
4x-3/7x-(+9x+1/8x)+4=0
We get rid of parentheses
4x-3/7x-9x-1/8x+4=0
We calculate fractions
4x-9x+(-24x)/56x^2+(-7x)/56x^2+4=0
We add all the numbers together, and all the variables
-5x+(-24x)/56x^2+(-7x)/56x^2+4=0
We multiply all the terms by the denominator
-5x*56x^2+(-24x)+(-7x)+4*56x^2=0
Wy multiply elements
-280x^3+224x^2+(-24x)+(-7x)=0
We get rid of parentheses
-280x^3+224x^2-24x-7x=0
We do not support expression: x^3

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