4x-3/7x+4=9x+1/8x

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Solution for 4x-3/7x+4=9x+1/8x equation: 



4x-3/7x+4=9x+1/8x

We move all terms to the left:

4x-3/7x+4-(9x+1/8x)=0



Domain of the equation: 7x!=0

x!=0/7

x!=0

x∈R





Domain of the equation: 8x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

4x-3/7x-(+9x+1/8x)+4=0

We get rid of parentheses

4x-3/7x-9x-1/8x+4=0

We calculate fractions


4x-9x+(-24x)/56x^2+(-7x)/56x^2+4=0

We add all the numbers together, and all the variables

-5x+(-24x)/56x^2+(-7x)/56x^2+4=0

We multiply all the terms by the denominator


-5x*56x^2+(-24x)+(-7x)+4*56x^2=0

Wy multiply elements

-280x^3+224x^2+(-24x)+(-7x)=0

We get rid of parentheses

-280x^3+224x^2-24x-7x=0

We do not support expression: x^3

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