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4x-32=58/2x
We move all terms to the left:
4x-32-(58/2x)=0
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
4x-(+58/2x)-32=0
We get rid of parentheses
4x-58/2x-32=0
We multiply all the terms by the denominator
4x*2x-32*2x-58=0
Wy multiply elements
8x^2-64x-58=0
a = 8; b = -64; c = -58;
Δ = b2-4ac
Δ = -642-4·8·(-58)
Δ = 5952
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5952}=\sqrt{64*93}=\sqrt{64}*\sqrt{93}=8\sqrt{93}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-8\sqrt{93}}{2*8}=\frac{64-8\sqrt{93}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+8\sqrt{93}}{2*8}=\frac{64+8\sqrt{93}}{16} $
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