4x-3=(x/2)+6

Solution for 4x-3=(x/2)+6 equation:

4x-3=(x/2)+6

We move all terms to the left:

4x-3-((x/2)+6)=0

We add all the numbers together, and all the variables

4x-((+x/2)+6)-3=0

We multiply all the terms by the denominator


4x*2)+6)-((+x-3*2)+6)=0

We add all the numbers together, and all the variables

4x*2)+6)-((x-6)+6)=0

We add all the numbers together, and all the variables

4x*2)+6)-((x=0

Wy multiply elements

8x^2=0

a = 8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·8·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{16}=0$