4x-3=3(x-2)+(x-3)

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Solution for 4x-3=3(x-2)+(x-3) equation:


Simplifying
4x + -3 = 3(x + -2) + (x + -3)

Reorder the terms:
-3 + 4x = 3(x + -2) + (x + -3)

Reorder the terms:
-3 + 4x = 3(-2 + x) + (x + -3)
-3 + 4x = (-2 * 3 + x * 3) + (x + -3)
-3 + 4x = (-6 + 3x) + (x + -3)

Reorder the terms:
-3 + 4x = -6 + 3x + (-3 + x)

Remove parenthesis around (-3 + x)
-3 + 4x = -6 + 3x + -3 + x

Reorder the terms:
-3 + 4x = -6 + -3 + 3x + x

Combine like terms: -6 + -3 = -9
-3 + 4x = -9 + 3x + x

Combine like terms: 3x + x = 4x
-3 + 4x = -9 + 4x

Add '-4x' to each side of the equation.
-3 + 4x + -4x = -9 + 4x + -4x

Combine like terms: 4x + -4x = 0
-3 + 0 = -9 + 4x + -4x
-3 = -9 + 4x + -4x

Combine like terms: 4x + -4x = 0
-3 = -9 + 0
-3 = -9

Solving
-3 = -9

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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