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4x-3x(x+2)=5(4-x)
We move all terms to the left:
4x-3x(x+2)-(5(4-x))=0
We add all the numbers together, and all the variables
4x-3x(x+2)-(5(-1x+4))=0
We multiply parentheses
-3x^2+4x-6x-(5(-1x+4))=0
We calculate terms in parentheses: -(5(-1x+4)), so:We add all the numbers together, and all the variables
5(-1x+4)
We multiply parentheses
-5x+20
Back to the equation:
-(-5x+20)
-3x^2-2x-(-5x+20)=0
We get rid of parentheses
-3x^2-2x+5x-20=0
We add all the numbers together, and all the variables
-3x^2+3x-20=0
a = -3; b = 3; c = -20;
Δ = b2-4ac
Δ = 32-4·(-3)·(-20)
Δ = -231
Delta is less than zero, so there is no solution for the equation
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