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4x-3x(x-2)=2x+4
We move all terms to the left:
4x-3x(x-2)-(2x+4)=0
We multiply parentheses
-3x^2+4x+6x-(2x+4)=0
We get rid of parentheses
-3x^2+4x+6x-2x-4=0
We add all the numbers together, and all the variables
-3x^2+8x-4=0
a = -3; b = 8; c = -4;
Δ = b2-4ac
Δ = 82-4·(-3)·(-4)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-4}{2*-3}=\frac{-12}{-6} =+2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+4}{2*-3}=\frac{-4}{-6} =2/3 $
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