4x-3x+6-8+12+x=20

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Solution for 4x-3x+6-8+12+x=20 equation: 



4x-3x+6-8+12+x=20

We move all terms to the left:

4x-3x+6-8+12+x-(20)=0

We add all the numbers together, and all the variables

2x-10=0

We move all terms containing x to the left, all other terms to the right

2x=10

x=10/2

x=5

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