4x-4+x=2(2x-3)+12

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Solution for 4x-4+x=2(2x-3)+12 equation: 



4x-4+x=2(2x-3)+12

We move all terms to the left:

4x-4+x-(2(2x-3)+12)=0

We add all the numbers together, and all the variables

5x-(2(2x-3)+12)-4=0



We calculate terms in parentheses: -(2(2x-3)+12), so:

2(2x-3)+12

We multiply parentheses

4x-6+12

We add all the numbers together, and all the variables

4x+6

Back to the equation:

-(4x+6)



We get rid of parentheses

5x-4x-6-4=0

We add all the numbers together, and all the variables

x-10=0

We move all terms containing x to the left, all other terms to the right

x=10

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