4x-4/x+3

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Solution for 4x-4/x+3 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

4*x-(4/x)+3 = 0

4*x-4*x^-1+3 = 0

4*x^1-4*x^-1+3*x^0 = 0

(4*x^2+3*x^1-4*x^0)/(x^1) = 0 // * x^2

x^1*(4*x^2+3*x^1-4*x^0) = 0

x^1

4*x^2+3*x-4 = 0

4*x^2+3*x-4 = 0

DELTA = 3^2-(-4*4*4)

DELTA = 73

DELTA > 0

x = (73^(1/2)-3)/(2*4) or x = (-73^(1/2)-3)/(2*4)

x = (73^(1/2)-3)/8 or x = (-(73^(1/2)+3))/8

x in { (-(73^(1/2)+3))/8, (73^(1/2)-3)/8} 

x in { (-(73^(1/2)+3))/8, (73^(1/2)-3)/8 }

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