4x-43+3x=10(3x-2)

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Solution for 4x-43+3x=10(3x-2) equation: 



4x-43+3x=10(3x-2)

We move all terms to the left:

4x-43+3x-(10(3x-2))=0

We add all the numbers together, and all the variables

7x-(10(3x-2))-43=0



We calculate terms in parentheses: -(10(3x-2)), so:

10(3x-2)

We multiply parentheses

30x-20

Back to the equation:

-(30x-20)



We get rid of parentheses

7x-30x+20-43=0

We add all the numbers together, and all the variables

-23x-23=0

We move all terms containing x to the left, all other terms to the right

-23x=23

x=23/-23

x=-1

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