4x-5(2x+1)=0x+(-5)

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Solution for 4x-5(2x+1)=0x+(-5) equation: 



4x-5(2x+1)=0x+(-5)

We move all terms to the left:

4x-5(2x+1)-(0x+(-5))=0

We multiply parentheses

4x-10x-(0x+(-5))-5=0



We calculate terms in parentheses: -(0x+(-5)), so:

0x+(-5)

We add all the numbers together, and all the variables

x-5

Back to the equation:

-(x-5)



We add all the numbers together, and all the variables

-6x-(x-5)-5=0

We get rid of parentheses

-6x-x+5-5=0

We add all the numbers together, and all the variables

-7x=0

x=0/-7

x=0

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