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4x-5(2x+1)=1x+(-5)
We move all terms to the left:
4x-5(2x+1)-(1x+(-5))=0
We multiply parentheses
4x-10x-(1x+(-5))-5=0
We calculate terms in parentheses: -(1x+(-5)), so:We add all the numbers together, and all the variables
1x+(-5)
We add all the numbers together, and all the variables
x-5
Back to the equation:
-(x-5)
-6x-(x-5)-5=0
We get rid of parentheses
-6x-x+5-5=0
We add all the numbers together, and all the variables
-7x=0
x=0/-7
x=0
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