4x-5(3x+10)=128

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Solution for 4x-5(3x+10)=128 equation: 



4x-5(3x+10)=128

We move all terms to the left:

4x-5(3x+10)-(128)=0

We multiply parentheses

4x-15x-50-128=0

We add all the numbers together, and all the variables

-11x-178=0

We move all terms containing x to the left, all other terms to the right

-11x=178

x=178/-11

x=-16+2/11

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