4x-5(3x+19)=126

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Solution for 4x-5(3x+19)=126 equation: 



4x-5(3x+19)=126

We move all terms to the left:

4x-5(3x+19)-(126)=0

We multiply parentheses

4x-15x-95-126=0

We add all the numbers together, and all the variables

-11x-221=0

We move all terms containing x to the left, all other terms to the right

-11x=221

x=221/-11

x=-20+1/11

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