4x-5(x+3)=(x+1)-2

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Solution for 4x-5(x+3)=(x+1)-2 equation: 



4x-5(x+3)=(x+1)-2

We move all terms to the left:

4x-5(x+3)-((x+1)-2)=0

We multiply parentheses

4x-5x-((x+1)-2)-15=0



We calculate terms in parentheses: -((x+1)-2), so:

(x+1)-2

We get rid of parentheses

x+1-2

We add all the numbers together, and all the variables

x-1

Back to the equation:

-(x-1)



We add all the numbers together, and all the variables

-1x-(x-1)-15=0

We get rid of parentheses

-1x-x+1-15=0

We add all the numbers together, and all the variables

-2x-14=0

We move all terms containing x to the left, all other terms to the right

-2x=14

x=14/-2

x=-7

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