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4x-5+7x=(x+3)1
We move all terms to the left:
4x-5+7x-((x+3)1)=0
We add all the numbers together, and all the variables
11x-((x+3)1)-5=0
We calculate terms in parentheses: -((x+3)1), so:
(x+3)1
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(x+3)1
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(x+3)1
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(x+3)1
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(x+3)1
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(x+3)1
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(x+3)1
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(x+3)1
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(x+3)1
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See similar equations:
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