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4x-5+x=4(3x+1)
We move all terms to the left:
4x-5+x-(4(3x+1))=0
We add all the numbers together, and all the variables
5x-(4(3x+1))-5=0
We calculate terms in parentheses: -(4(3x+1)), so:We get rid of parentheses
4(3x+1)
We multiply parentheses
12x+4
Back to the equation:
-(12x+4)
5x-12x-4-5=0
We add all the numbers together, and all the variables
-7x-9=0
We move all terms containing x to the left, all other terms to the right
-7x=9
x=9/-7
x=-1+2/7
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