4x-5=12x+27

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Solution for 4x-5=12x+27 equation: 



4x-5=12x+27

We move all terms to the left:

4x-5-(12x+27)=0

We get rid of parentheses

4x-12x-27-5=0

We add all the numbers together, and all the variables

-8x-32=0

We move all terms containing x to the left, all other terms to the right

-8x=32

x=32/-8

x=-4

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