4x-5=3x(x-2)+13

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Solution for 4x-5=3x(x-2)+13 equation: 



4x-5=3x(x-2)+13

We move all terms to the left:

4x-5-(3x(x-2)+13)=0



We calculate terms in parentheses: -(3x(x-2)+13), so:

3x(x-2)+13

We multiply parentheses

3x^2-6x+13

Back to the equation:

-(3x^2-6x+13)



We get rid of parentheses

-3x^2+4x+6x-13-5=0

We add all the numbers together, and all the variables

-3x^2+10x-18=0

a = -3; b = 10; c = -18;
Δ = b2-4ac
Δ = 102-4·(-3)·(-18)
Δ = -116
Delta is less than zero, so there is no solution for the equation

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