4x-6+3(x+3-6)-48+2x-4x+(3x-6)-5=x+3(x-6+4x)-5

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Solution for 4x-6+3(x+3-6)-48+2x-4x+(3x-6)-5=x+3(x-6+4x)-5 equation: 



4x-6+3(x+3-6)-48+2x-4x+(3x-6)-5=x+3(x-6+4x)-5

We move all terms to the left:

4x-6+3(x+3-6)-48+2x-4x+(3x-6)-5-(x+3(x-6+4x)-5)=0

We add all the numbers together, and all the variables

4x+3(x-3)+2x-4x+(3x-6)-(x+3(5x-6)-5)-6-48-5=0

We add all the numbers together, and all the variables

2x+3(x-3)+(3x-6)-(x+3(5x-6)-5)-59=0

We multiply parentheses

2x+3x+(3x-6)-(x+3(5x-6)-5)-9-59=0

We get rid of parentheses

2x+3x+3x-(x+3(5x-6)-5)-6-9-59=0



We calculate terms in parentheses: -(x+3(5x-6)-5), so:

x+3(5x-6)-5

We multiply parentheses

x+15x-18-5

We add all the numbers together, and all the variables

16x-23

Back to the equation:

-(16x-23)



We add all the numbers together, and all the variables

8x-(16x-23)-74=0

We get rid of parentheses

8x-16x+23-74=0

We add all the numbers together, and all the variables

-8x-51=0

We move all terms containing x to the left, all other terms to the right

-8x=51

x=51/-8

x=-6+3/8

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