4x-6-(2x+3)=2-3(8x-2)

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Solution for 4x-6-(2x+3)=2-3(8x-2) equation: 



4x-6-(2x+3)=2-3(8x-2)

We move all terms to the left:

4x-6-(2x+3)-(2-3(8x-2))=0

We get rid of parentheses

4x-2x-(2-3(8x-2))-3-6=0



We calculate terms in parentheses: -(2-3(8x-2)), so:

2-3(8x-2)

determiningTheFunctionDomain
-3(8x-2)+2

We multiply parentheses

-24x+6+2

We add all the numbers together, and all the variables

-24x+8

Back to the equation:

-(-24x+8)



We add all the numbers together, and all the variables

2x-(-24x+8)-9=0

We get rid of parentheses

2x+24x-8-9=0

We add all the numbers together, and all the variables

26x-17=0

We move all terms containing x to the left, all other terms to the right

26x=17

x=17/26

x=17/26

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