4x-64=72+12x

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Solution for 4x-64=72+12x equation: 



4x-64=72+12x

We move all terms to the left:

4x-64-(72+12x)=0

We add all the numbers together, and all the variables

4x-(12x+72)-64=0

We get rid of parentheses

4x-12x-72-64=0

We add all the numbers together, and all the variables

-8x-136=0

We move all terms containing x to the left, all other terms to the right

-8x=136

x=136/-8

x=-17

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