4x-7(x+3)=-36+3(x+2)-2(2x+7)

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Solution for 4x-7(x+3)=-36+3(x+2)-2(2x+7) equation: 



4x-7(x+3)=-36+3(x+2)-2(2x+7)

We move all terms to the left:

4x-7(x+3)-(-36+3(x+2)-2(2x+7))=0

We multiply parentheses

4x-7x-(-36+3(x+2)-2(2x+7))-21=0



We calculate terms in parentheses: -(-36+3(x+2)-2(2x+7)), so:

-36+3(x+2)-2(2x+7)

determiningTheFunctionDomain
3(x+2)-2(2x+7)-36

We multiply parentheses

3x-4x+6-14-36

We add all the numbers together, and all the variables

-1x-44

Back to the equation:

-(-1x-44)



We add all the numbers together, and all the variables

-3x-(-1x-44)-21=0

We get rid of parentheses

-3x+1x+44-21=0

We add all the numbers together, and all the variables

-2x+23=0

We move all terms containing x to the left, all other terms to the right

-2x=-23

x=-23/-2

x=11+1/2

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