4x-7(x+3)=-36+3(x+2)=2(2x+7)

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Solution for 4x-7(x+3)=-36+3(x+2)=2(2x+7) equation: 



4x-7(x+3)=-36+3(x+2)=2(2x+7)

We move all terms to the left:

4x-7(x+3)-(-36+3(x+2))=0

We multiply parentheses

4x-7x-(-36+3(x+2))-21=0



We calculate terms in parentheses: -(-36+3(x+2)), so:

-36+3(x+2)

determiningTheFunctionDomain
3(x+2)-36

We multiply parentheses

3x+6-36

We add all the numbers together, and all the variables

3x-30

Back to the equation:

-(3x-30)



We add all the numbers together, and all the variables

-3x-(3x-30)-21=0

We get rid of parentheses

-3x-3x+30-21=0

We add all the numbers together, and all the variables

-6x+9=0

We move all terms containing x to the left, all other terms to the right

-6x=-9

x=-9/-6

x=1+1/2

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