4x-7+8(1-x)=22x+1-12(2x-4)

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Solution for 4x-7+8(1-x)=22x+1-12(2x-4) equation: 



4x-7+8(1-x)=22x+1-12(2x-4)

We move all terms to the left:

4x-7+8(1-x)-(22x+1-12(2x-4))=0

We add all the numbers together, and all the variables

4x+8(-1x+1)-(22x+1-12(2x-4))-7=0

We multiply parentheses

4x-8x-(22x+1-12(2x-4))+8-7=0



We calculate terms in parentheses: -(22x+1-12(2x-4)), so:

22x+1-12(2x-4)

determiningTheFunctionDomain
22x-12(2x-4)+1

We multiply parentheses

22x-24x+48+1

We add all the numbers together, and all the variables

-2x+49

Back to the equation:

-(-2x+49)



We add all the numbers together, and all the variables

-4x-(-2x+49)+1=0

We get rid of parentheses

-4x+2x-49+1=0

We add all the numbers together, and all the variables

-2x-48=0

We move all terms containing x to the left, all other terms to the right

-2x=48

x=48/-2

x=-24

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