4x-8/2x=0

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Solution for 4x-8/2x=0 equation:



4x-8/2x=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
We multiply all the terms by the denominator
4x*2x-8=0
Wy multiply elements
8x^2-8=0
a = 8; b = 0; c = -8;
Δ = b2-4ac
Δ = 02-4·8·(-8)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16}{2*8}=\frac{-16}{16} =-1 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16}{2*8}=\frac{16}{16} =1 $

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