4x-8/x=12

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Solution for 4x-8/x=12 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

4*x-(8/x) = 12 // - 12

4*x-(8/x)-12 = 0

4*x-8*x^-1-12 = 0

4*x^1-8*x^-1-12*x^0 = 0

(4*x^2-12*x^1-8*x^0)/(x^1) = 0 // * x^2

x^1*(4*x^2-12*x^1-8*x^0) = 0

x^1

4*x^2-12*x-8 = 0

4*x^2-12*x-8 = 0

DELTA = (-12)^2-(-8*4*4)

DELTA = 272

DELTA > 0

x = (272^(1/2)+12)/(2*4) or x = (12-272^(1/2))/(2*4)

x = (4*17^(1/2)+12)/8 or x = (12-4*17^(1/2))/8

x in { (12-4*17^(1/2))/8, (4*17^(1/2)+12)/8}

x in { (12-4*17^(1/2))/8, (4*17^(1/2)+12)/8 }

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