4x-8=4((2x+1)/3)

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Solution for 4x-8=4((2x+1)/3) equation:



4x-8=4((2x+1)/3)
We move all terms to the left:
4x-8-(4((2x+1)/3))=0
We multiply all the terms by the denominator
4x*3))-(4((2x+1)-8*3))=0
We add all the numbers together, and all the variables
4x*3))-(4((2x+1)=0
Wy multiply elements
12x^2=0
a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{24}=0$

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