4x-8=8+x(2x-4)

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Solution for 4x-8=8+x(2x-4) equation: 



4x-8=8+x(2x-4)

We move all terms to the left:

4x-8-(8+x(2x-4))=0



We calculate terms in parentheses: -(8+x(2x-4)), so:

8+x(2x-4)

determiningTheFunctionDomain
x(2x-4)+8

We multiply parentheses

2x^2-4x+8

Back to the equation:

-(2x^2-4x+8)



We get rid of parentheses

-2x^2+4x+4x-8-8=0

We add all the numbers together, and all the variables

-2x^2+8x-16=0

a = -2; b = 8; c = -16;
Δ = b2-4ac
Δ = 82-4·(-2)·(-16)
Δ = -64
Delta is less than zero, so there is no solution for the equation

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