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4x-9+3x=2(3x-2)+x-5
We move all terms to the left:
4x-9+3x-(2(3x-2)+x-5)=0
We add all the numbers together, and all the variables
7x-(2(3x-2)+x-5)-9=0
We calculate terms in parentheses: -(2(3x-2)+x-5), so:We get rid of parentheses
2(3x-2)+x-5
We add all the numbers together, and all the variables
x+2(3x-2)-5
We multiply parentheses
x+6x-4-5
We add all the numbers together, and all the variables
7x-9
Back to the equation:
-(7x-9)
7x-7x+9-9=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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