4x-x(x-2)+1/2(x2+3)=2(x+3)-x(x-4)

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Solution for 4x-x(x-2)+1/2(x2+3)=2(x+3)-x(x-4) equation: 



4x-x(x-2)+1/2(x2+3)=2(x+3)-x(x-4)

We move all terms to the left:

4x-x(x-2)+1/2(x2+3)-(2(x+3)-x(x-4))=0



Domain of the equation: 2(x2+3)!=0

x∈R



We add all the numbers together, and all the variables

1/2(+x^2+3)+4x-x(x-2)-(2(x+3)-x(x-4))=0

We multiply parentheses

1/2(+x^2+3)-x^2+4x+2x-(2(x+3)-x(x-4))=0

We multiply all the terms by the denominator


-x^2*2(+x^2+3)+4x*2(+x^2+3)+2x*2(+x^2+3)-((2(x+3)-x(x-4)))*2(+x^2+3)+1=0



We calculate terms in parentheses: -((2(x+3)-x(x-4)))*2(+x^2+3), so:

(2(x+3)-x(x-4)))*2(+x^2+3

determiningTheFunctionDomain
x^2+(2(x+3)-x(x-4)))*2(+3

Back to the equation:

-(x^2+(2(x+3)-x(x-4)))*2(+3)



We add all the numbers together, and all the variables

-x^2*2(+x^2+3)+4x*2(+x^2+3)+2x*2(+x^2+3)-(x^2+(2(x+3)-x(x-4)))*23+1=0

Wy multiply elements

-2x^3(++8x^2(++4x^2(+-(x^2+(2(x+3)-x(x-4)))*23+1=0

We do not support expression: x^3(

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