4x/(x+1)=7-(4/(x+1))

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Solution for 4x/(x+1)=7-(4/(x+1)) equation:


D( x )

x+1 = 0

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x in (-oo:-1) U (-1:+oo)

(4*x)/(x+1) = 7-(4/(x+1)) // - 7-(4/(x+1))

(4*x)/(x+1)+4/(x+1)-7 = 0

(4*x)/(x+1)+4/(x+1)+(-7*(x+1))/(x+1) = 0

4*x-7*(x+1)+4 = 0

4*x-7*x-7+4 = 0

-3*x-3 = 0

(-3*x-3)/(x+1) = 0

(-3*x-3)/(x+1) = 0 // * x+1

-3*x-3 = 0

-3*x-3 = 0 // + 3

-3*x = 3 // : -3

x = 3/(-3)

x = -1

x in { -1}

x belongs to the empty set

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