4x/3x+5=4x/5x

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Solution for 4x/3x+5=4x/5x equation: 



4x/3x+5=4x/5x

We move all terms to the left:

4x/3x+5-(4x/5x)=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R





Domain of the equation: 5x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

4x/3x-(+4x/5x)+5=0

We get rid of parentheses

4x/3x-4x/5x+5=0

We calculate fractions


(-12x^2)/15x^2+20x^2/15x^2+5=0

We multiply all the terms by the denominator


(-12x^2)+20x^2+5*15x^2=0

We add all the numbers together, and all the variables

20x^2+(-12x^2)+5*15x^2=0

Wy multiply elements

20x^2+(-12x^2)+75x^2=0

We get rid of parentheses

20x^2-12x^2+75x^2=0

We add all the numbers together, and all the variables

83x^2=0

a = 83; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·83·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{166}=0$

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