4x/5+3(1/2+4x/2)=7/2+11x/5

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Solution for 4x/5+3(1/2+4x/2)=7/2+11x/5 equation:


x in (-oo:+oo)

3*((4*x)/2+1/2)+(4*x)/5 = (11*x)/5+7/2 // - (11*x)/5+7/2

3*((4*x)/2+1/2)+(4*x)/5-((11*x)/5)-(7/2) = 0

3*((4*x)/2+1/2)+(4*x)/5+(-11/5)*x-7/2 = 0

3*(2*x+1/2)+(4*x)/5+(-11*x)/5-7/2 = 0

(2*3*5*(2*x+1/2))/(2*5)+(2*4*x)/(2*5)+(-11*2*x)/(2*5)+(-7*5)/(2*5) = 0

2*3*5*(2*x+1/2)+2*4*x-11*2*x-7*5 = 0

68*x-22*x-35+15 = 0

46*x-35+15 = 0

46*x-20 = 0

(46*x-20)/(2*5) = 0

(46*x-20)/(2*5) = 0 // * 2*5

46*x-20 = 0

46*x-20 = 0 // + 20

46*x = 20 // : 46

x = 20/46

x = 10/23

x = 10/23

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