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4x/5-2(x-3)=x-5
We move all terms to the left:
4x/5-2(x-3)-(x-5)=0
We multiply parentheses
4x/5-2x-(x-5)+6=0
We get rid of parentheses
4x/5-2x-x+5+6=0
We multiply all the terms by the denominator
4x-2x*5-x*5+5*5+6*5=0
We add all the numbers together, and all the variables
4x-2x*5-x*5+55=0
Wy multiply elements
4x-10x-5x+55=0
We add all the numbers together, and all the variables
-11x+55=0
We move all terms containing x to the left, all other terms to the right
-11x=-55
x=-55/-11
x=+5
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