4x/8x=12-8x

Solution for 4x/8x=12-8x equation:

4x/8x=12-8x

We move all terms to the left:

4x/8x-(12-8x)=0


Domain of the equation: 8x!=0

x!=0/8

x!=0

x∈R


We add all the numbers together, and all the variables

4x/8x-(-8x+12)=0

We get rid of parentheses

4x/8x+8x-12=0

We multiply all the terms by the denominator


4x+8x*8x-12*8x=0

Wy multiply elements

64x^2+4x-96x=0

We add all the numbers together, and all the variables

64x^2-92x=0

a = 64; b = -92; c = 0;
Δ = b2-4ac
Δ = -922-4·64·0
Δ = 8464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8464}=92$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-92)-92}{2*64}=\frac{0}{128}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-92)+92}{2*64}=\frac{184}{128}
=1+7/16
$