4x/x-3-x/2=12/x-3

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Solution for 4x/x-3-x/2=12/x-3 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(4*x)/x-(x/2)-3 = 12/x-3 // - 12/x-3

(4*x)/x-(x/2)-(12/x)-3+3 = 0

(4*x)/x-(x/2)-12*x^-1-3+3 = 0

4*x^0-1/2*x^1-12*x^-1 = 0

(4*x^1-1/2*x^2-12*x^0)/(x^1) = 0 // * x^2

x^1*(4*x^1-1/2*x^2-12*x^0) = 0

x^1

(-1/2)*x^2+4*x-12 = 0

(-1/2)*x^2+4*x-12 = 0

DELTA = 4^2-(-12*4*(-1/2))

DELTA = -8

DELTA < 0

x in { } 

x belongs to the empty set

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