4x2(x-3)=3x+x-12

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Solution for 4x2(x-3)=3x+x-12 equation: 



4x^2(x-3)=3x+x-12

We move all terms to the left:

4x^2(x-3)-(3x+x-12)=0

We add all the numbers together, and all the variables

4x^2(x-3)-(4x-12)=0

We get rid of parentheses

4x^2(x-3)-4x+12=0

We move all terms containing x to the left, all other terms to the right

4x^2(x-3)-4x=-12

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