4x2+-65x-375=0

Solution for 4x2+-65x-375=0 equation:

4x^2+-65x-375=0

We add all the numbers together, and all the variables

4x^2-65x=0

a = 4; b = -65; c = 0;
Δ = b2-4ac
Δ = -652-4·4·0
Δ = 4225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4225}=65$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-65)-65}{2*4}=\frac{0}{8}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-65)+65}{2*4}=\frac{130}{8}
=16+1/4
$