4x2+100x=600

Solution for 4x2+100x=600 equation:

4x^2+100x=600

We move all terms to the left:

4x^2+100x-(600)=0

a = 4; b = 100; c = -600;
Δ = b2-4ac
Δ = 1002-4·4·(-600)
Δ = 19600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{19600}=140$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-140}{2*4}=\frac{-240}{8}
=-30
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+140}{2*4}=\frac{40}{8}
=5
$