4x2+12x+9x2=0

Solution for 4x2+12x+9x2=0 equation:

4x^2+12x+9x^2=0

We add all the numbers together, and all the variables

13x^2+12x=0

a = 13; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·13·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*13}=\frac{-24}{26}
=-12/13
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*13}=\frac{0}{26}
=0
$